t^2=5121.65t

Solution for t^2=5121.65t equation:

t^2=5121.65t

We move all terms to the left:

t^2-(5121.65t)=0

We add all the numbers together, and all the variables

t^2-(+5121.65t)=0

We get rid of parentheses

t^2-5121.65t=0

a = 1; b = -5121.65; c = 0;
Δ = b2-4ac
Δ = -5121.652-4·1·0
Δ = 26231298.7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5121.65)-\sqrt{26231298.7225}}{2*1}=\frac{5121.65-\sqrt{26231298.7225}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5121.65)+\sqrt{26231298.7225}}{2*1}=\frac{5121.65+\sqrt{26231298.7225}}{2}
$